Lecture 11 - Legendre Symbols and Gauss' Lemma
Definition - Let \(p\) be a prime. If \(\gcd(a,p) = 1\) and \(a\equiv b^2\bmod{p}\) for some \(b\), then we say that \(a\) is a quadratic residue modulo \(p\). We sometimes say \(a\) is a QR. If \(\gcd(a,p) = 1\) and \(a\) is not a QR, then we say that \(a\) is an NR (for not a quadratic residue). If \(p\mid a\) then we do not consider \(a\) to be either QR or NR.
Definition - Let \(p\) be a prime and let \(a\in \mathbb{Z}\). Then we define the Legendre symbol \(\left(\frac{a}{p}\right)\) as follows
\[\left(\frac{a}{p}\right) = \left\{ \begin{array}{ll} 1 &\text{if }a \text{ is a QR modulo }p\\ 0 &\text{if }p\mid a\\ -1&\text{if }a\text{ is a NR modulo }p \end{array}\right.\]Proposition. Let \(p\) be an odd prime and let \(\gcd(a,p) = 1\). Then
\[\left(\frac{a}{p}\right) \equiv a^{(p-1)/2}\bmod{p}.\]Corollary. Let \(p\) be an odd prime. Then
\[\left(\frac{-1}{p}\right) = (-1)^{(p-1)/2}.\]The goal of the following two videos is to look at Gauss’ Lemma and applying it to calculate \(\left(\frac{2}{p}\right)\).
In the above video, we have
\[S = \{1,2,\ldots,(p-1)/2\}\] \[S' = \{b,2b,\ldots, \frac{p-1}{2} b\}.\]Proposition. Let \(p\) be an odd prime and \(\gcd(b,p) = 1\). Then for each \(a\) with \(\gcd(a,p) = 1\), there exists unique \(s\in S\) and \(\epsilon\in \{1,-1\}\) such that
\[a\equiv \epsilon s\bmod{p}.\]Similarly, there exists unique \(\epsilon'\in\{1,-1\}\) and \(s'\in S'\) with
\[a\equiv \epsilon' s'\bmod{p}.\]Then in the following video, we apply this to prove Gauss’ Lemma and calculate the Legendre symbol \((2/p)\).
For each \(r = 1,2,\ldots, (p-1)/2\) we write \(br \equiv \epsilon_r s_r\bmod{p}\) with \(\epsilon_r = \pm 1\) and \(s_r\in S\).
Gauss’ Lemma. We have
\[\left(\frac{b}{p}\right) = \epsilon_1\epsilon_2\cdots \epsilon_{(p-1)/2}.\]Corollary. We have
\[\left(\frac{2}{p}\right) = (-1)^{(p^2-1)/8}.\]